10t^2=t

Solution for 10t^2=t equation:

10t^2=t

We move all terms to the left:

10t^2-(t)=0

We add all the numbers together, and all the variables

10t^2-1t=0

a = 10; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·10·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*10}=\frac{0}{20}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*10}=\frac{2}{20}
=1/10
$